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2 years ago

How would the amount of potential energy stored in the bungee cord compare to

1 answer:

3 0

If the spring constant of the bungee rope is greater than that of a rubber band, it will have more elastic potential energy. However, if the spring constant of the rubber band is greater than that of the bungee rope, the rubber band will have more elastic potential energy.

<h3>Elastic Potential energy </h3>

Elastic Potential energy is the stored in a elastic string which has been compressed or stretched.

The formula for calculating elastic potential energy is given as:

Elastic Potential = 1/2 Kx^2

where

K is the spring constant of elastic material
x is the distance if compression or stretch

The elastic potential of an elastic material depends on the spring constant and the distance stretched or compressed.

Since the bungee rope and the rubber band are stretched the same distance, their elastic potential energy depends on their spring constant.

Therefore, if spring constant of the bungee rope is greater than that of a rubber band, it will have more elastic potential energy. However, if the spring constant of the rubber band is greater than that of the bungee rope, the rubber band will have more elastic potential energy.

Learn more about elastic potential energy at: brainly.com/question/1075827

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PLZ hurry! Thank you

Alenkinab [10]

Answer:do it again

Explanation:

It will work

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2 years ago

The drawing shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel a

Pavel [41]

Answer:

$F=27.39N$

Explanation:

Take sum of torques at the point the step touches the wheel, that eliminates two torques

Σ $T=T_{N}+T_{f}+T_{W}$

Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force

$T_{N}=0$

The perpendicular lever arm for the F force is R-h

$T_{f}=F*(r-h)$

And the T of gravity according to the image

$T_{W}=W*(\sqrt{r^2-(r-h)^2}$

Σ $T=0$

$T_{N}+T_{f}+T_{W}=0$

$F*(r-h)+W*(\sqrt{r^2-(r-h)^2}=0$

$F=\frac{W*(\sqrt{r^2-(r-h)^2}}{r-h}$

$F=\frac{24.9 N*(\sqrt{0.336^2-(0.336-0.110)^2}}{(0.336-0.11)}$

$F=27.39N$

4 0

2 years ago

In a water park, people walk a distance of 20 meters up an inclined ramp before getting on a water slide. If the spot from where

Elenna [48]

Thank you for posting your Physics question here. I hope the answer helps. Upon calculating the ramp with the horizontal the answer is 20.49 Deg. Below is the solution:

Y = 7 m.
<span>r = 20 m. </span>

<span>sinA = Y/r = 7/20 = 0.35. </span>
<span>A = 20.49 Deg.</span>

8 0

2 years ago

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Vladimir79 [104]

I believe it would be 2m/s.

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2 years ago

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Compare and contrast the theories about the origin of the universe

Vaselesa [24]

Answer:

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Explanation:

hope this helps tho i don't quite know what you mean

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2 years ago