Using Kepler's 3rd law which is: T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds :
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m
Answer:
Isotope of carbon-12.
Explanation:
The MOLE is a unit of measurement of the amount of a pure substance which contains exactly the same number of chemical units which could be (Atoms, molecules etc.) posses atoms in exactly
grams of isotope of carbon-12 (i.e.,
).
So, The mole is the Notation used for an amount
as same the 12 number is used for dozen for making count of Bananas and many more.
The
is known as the fundamental constant names Avogadro's number (
), It is in the honor of Italian scientist Amedeo Avogadro.
The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere
.
Explanation:
- Assume the wires are ideal with zero resistance.
- The current passing through the circuit will be
I = V/R = 12/2 = 6.000 A.
Answer:
Explanation:
The distance of a fringe from centre is proportional to wavelength of light
and inversely proportional to separation of slits. The expression for distance x is given by
x = nλ D / d
where λ is wave length , D is screen distance and d is slit separation.
So first option only is correct because
1 ) the wavelength of blue light is less than that of red
2) Intensity of light does not affect distance of fringe from the centre.
3.
Diffraction symbolises bending of light around sharp edges like slits or boundaries of opaque objects etc.Due to this reason , we do not observe sharp boundary of shadow of an object. Instead around the boundary of shadow, we observe bands of bright and dark color which are also called fringes.
The phenomena of diffraction is explained by wave theory of light.
Answer:
16.87 m/s
Explanation:
To find the speed of the car at the top, when the normal force is equal the gravitational force, we just need to equate both forces:


is the centripetal acceleration in the loop:

So we have that:




So, using the gravity = 9.81 m/s^2 and the radius = 29 meters, we have:


The speed of the car is 16.87 m/s at the top.