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2 years ago

Which material will heat up the most quickly if placed near a heat source?

Physics

2 answers:

Thepotemich [5.8K]2 years ago

7 0

Answer:

Metal

Explanation:

Just answered on Apex

Vera_Pavlovna [14]2 years ago

3 0

Answer:

Metal

Explanation: Apex

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What is the definition of mass.

kozerog [31]

A coherent, typically large body of matter with no definitive shape
Hope this helps good luck

6 0

2 years ago

A photon has a momentum of 5.55 x 10-27 kg-m/s. (a) What is the photon's wavelength? nm (b) To what part of the electromagnetic

Brrunno [24]

Explanation:

It is given that,

Momentum of the photon, $p=5.55\times 10^{-27}\ kg-m/s$

(a) We need to find the wavelength of this photon. It can be calculated using the concept of De-broglie wavelength.

$\lambda=\dfrac{h}{p}$

h is the Planck's constant

$\lambda=\dfrac{6.67\times 10^{-34}\ Js}{5.55\times 10^{-27}\ kg-m/s}$

$\lambda=1.2\times 10^{-7}\ m$

$\lambda=120\ nm$

(b) The wavelength lies in the group of ultraviolet rays. The wavelength of UV rays lies in between 400 nm to 10 nm.

3 0

3 years ago

You lower the temperature of a sample of liquid carbon disulfide from 90.3 ∘ C until its volume contracts by 0.507 % of its init

Lady_Fox [76]

Answer:

$T_{f}$ = 85.89 ° C

Explanation:

The linear thermal expansion process is given by

ΔL = L α ΔT

For the three-dimensional case, the expression takes the form

ΔV = V β ΔT

Let's apply this equation to our case

ΔV / V = -0.507% = -0.507 10-2

ΔT = (ΔV / V) 1 /β

ΔT = -0.507 10⁻² 1 / 1.15 10⁻³

ΔT = -4.409

$T_{f}$ –T₀ = 4,409

$T_{f}$ = T₀ - 4,409

$T_{f}$ = 90.3-4409

$T_{f}$ = 85.89 ° C

6 0

3 years ago

Read 2 more answers

The junction rule describes the conservation of which quantity? Note that this rule applies only to circuits that are in a stead

denis-greek [22]

Explanation:

The junction rule says that the sum of the currents going into a junction must equal the sum of the currents leaving a junction. This describes the conservation of current.

5 0

2 years ago

Read 2 more answers

After applying sunscreen, Cherie lies in the summer sun to get a tan. The ultraviolet light responsible for tanning has a wavele

KIM [24]

Answer:

The photons that burn, emit more energy.

Explanation:

The energy of the ultraviolet photons can be determined by means of the following equation:

$E = h\nu$ (1)

Equation 1 can be rewritten in terms of $\lamba$

Since, $c = \nu \lambda$

$\nu = \frac{c}{\lambda}$

$E = \frac{hc}{\lambda}$ (2)

Where h is the planck's constant, c is the speed of light and $\lambda$ is the wavelength.

Case for the photon of with $\lambda = 310nm$

$\lambda = 310nm . \frac{1x10^{-9}m}{1nm}$ ⇒ $3.1x10^{-7}m$

$E = \frac{hc}{\lambda}$

$E = \frac{(6.626x10^{-34}J.s)(3x10^{8}m/s)}{3.1x10^{-7}m}$

$E = 6.412x10^{-19}J$

Case for the photon of with $\lambda = 280nm$

$\lambda = 280nm . \frac{1x10^{-9}m}{1nm}$ ⇒ $2.8x10^{-7}m$

$E = \frac{hc}{\lambda}$

$E = \frac{(6.626x10^{-34}J.s)(3x10^{8}m/s)}{2.8x10^{-7}m}$

$E = 7.099x10^{-19}J$

Hence, the photons that burn, emit more energy.

4 0

2 years ago