(a) 25lx
(b) 11.11lx
<u>Explanation:</u>
Illuminance is inversely proportional to the square of the distance.
So,

where, k is a constant
So,
(a)
If I = 100lx and r₂ = 2r Then,

Dividing both the equation we get

When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx
(b)
If I = 100lx and r₂ = 3r Then,

Dividing equation 1 and 3 we get

When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx
Answer:
Explanation:
The earth makes in 365 day 1 revolution
The earth makes in 1 day 1 / 365 revolutions
1 / 365 revolution per day
n = 1 / 365 per day .
n is called frequency of revolutions .
Angular velocity = 2π n
= 2 π x 1 / 365
= .0172 radian / day
Answer:
m =
x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m =
x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass
Answer:
Real image
Explanation:
The picture is real, but it is reversed and tiny. An picture generated by a pinhole camera has certain features. As compared item, the image created by a pinhole camera is normally pretty small and looks reversed both on the vertically and horizontally axis.
The height of the rail on top of the press box where the ball was dropped from is 11.025 m.
The given parameters:
- Time of motion of the ball, t = 1.5 s
- Let the height of the rail = h
<h3>Maximum height of fall;</h3>
- The maximum height through which the ball was dropped from is calculated by applying second equation of motion;

Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.
Learn more about height of projectiles here: brainly.com/question/10008919