True: when there is an angle between force and displacement,
Explanation:
The work done by a force when pushing/pulling an object is given by the equation
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
We have two extreme cases:
- When the force is parallel to the displacement, then and
, so the work done is maximum and simply becomes
- When the force is perpendicular to the displacement, then and
, so the work done is zero.
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Answer:
B = 62.9 N
Explanation:
This is an exercise on Archimedes' principle, where the thrust force equals the weight of the liquid
B = ρ g V
write the equilibrium equation
T + B -W = 0
B = W- T (1)
use the density to write the weight
ρ = m / V
m = ρ V
W = ρ g V
substitute in 1
B = m g -T
B = g V - T
To finish the calculation, the density of the material must be known, suppose it is steel \rho_{body} = 7850 kg / m³
calculate
B = 7850 9.8 1.20 10⁻³ - 29.4
B = 92.3 - 29.4
B = 62.9 N
Answer:
62.06 g/mol
Explanation:
We are given that a solution containing 10 g of an unknown liquid and 90 g
Given mass of solute ==10 g
Given mass of solvent==90 g
Freezing point of solution =-3.33C
Freezing point of solvent =C
Change in freezing point =Depression in freezing point
=Freezing point of solvent - freezing point of solution=0+3.33=
Hence, molar mass of unknown liquid is 62.06g/mol.
Try the solutions described in the attached picture, note the answers are marked with green colour.
