The observed value of z (test statistic) is greater than 1.96 (the test statistic does fall into the rejection region), so Reject H₀ .
p₁ = the proportion of the non-smoker population who reply "yes"
p₂ = the proportion of the smoker population who reply "yes," then we are interested in testing the null hypothesis
H₀: p₁ = p₂
Alternate hypothesis:
Hₐ: p₁≠p₂
That implies then that the test statistic for testing:
H₀ : p1 = p2
Hₐ : p1 ≠ p2. (Two – tailed)
n1 = 605, y1 = 351
p1 = y1 / n1
= 351/605
≈ 0.58
n2 = 195, y2 = 41.
p2 = y2/n2
= 41 / 195
≈0.21
p = y1 + y2 / n1 + n2
= 351 + 41 / 605 + 195
= 392 / 800
= 0.49
The test statistic is

z =
= 8.988
critical region for α = 0.01
z = 2.576
The observed value of z (test statistic) is greater than 1.96 (the test statistic does fall into the rejection region),
so Reject H₀ .
To learn more about hypothesis testing from the given link
brainly.com/question/4232174
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7 per ticket, so 7x
R = revenue, total cost
B. R(x) = 7x
Answer:
x + 3y = 5
5x - 3y = 7
Add up both equations, then:
6x = 12
=> x = 2
=> y = (5 - 2)/3 = 1
Answer:
x = 6, y =3
Step-by-step explanation:
4x-7y=3
x-7y=-15
Multiply the first equation by -1
-4x+7y=-3
Then add this to the second equation to eliminate y
-4x+7y=-3
x-7y=-15
------------------
-3x +0y = -18
-3x = -18
Divide by -3
-3x/-3 = -18/-3
x = 6
Now find y
x -7y = -15
6 -7y = -15
Subtract 6 from each side
6-7y-6 = -15-6
-7y = -21
Divide by -7
-7y/-7 = -21/-7
y =3