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Alexxx [7]
3 years ago
12

1/4(16p+8) ÷ 2(p+2)someone help​

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer: 1/2(16p+8)(p+2)

Explanation: There is a lot to do, but basically you must simplify the equation and then multiply by 4 on both sides

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A. 12 <br> b. 14<br> c. 8<br> d. 6
jolli1 [7]

Answer:

  d.  6

Step-by-step explanation:

The product of lengths to the near and far intersection points is the same for both secants:

  PB×PA = PD×PC

We can use this relation to solve for x, then use the value of x to find PD.

  7×12 = (3x)(7x)

  4 = x² . . . . . . . . . divide by 21

  2 = x . . . . . . . . . . take the square root

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  PD = 3x = 3·2

  PD = 6

5 0
3 years ago
Solve for t.<br><br> -5 − 2t = 3t
allsm [11]
T is equal to -1.
  1. <em>Add 2t to both sides of the equation.</em> -5 = 5t
  2. <em>Divide both sides of the equation by -5.</em> 1 = -t
  3. <em>Multiply both sides of the equation by -1.</em> -1 = t
4 0
3 years ago
Read 2 more answers
I NEED HELP WITH THIS PICTURE IS PROVIDED
RideAnS [48]
Is this an exam? Nehshdgdsusu
7 0
2 years ago
Tara rolled 4 6 8 2 8 3 1 what is the greatest number she can make using each digit once
andreyandreev [35.5K]

8,864,321

just put in order greatest to least

7 0
3 years ago
An accelerated life test on a large number of type-D alkaline batteries revealed that the mean life for a particular use before
zheka24 [161]

Answer:

68.2% of the batteries failed between 17.8 and 20.2 hours.

95.44% of the batteries failed between 16.6 and 21.4 hours.

99.97% of the batteries failed between 15.4 and 22.6 hours.

Step-by-step explanation:

The 68-95-99.7 states that, for a normally distributed sample:

68.26% of the measures are within 1 standard deviation of the sample.

95.44% of the measures are within 2 standard deviations of the sample.

99.97% of the measures are within 3 standard deviations of the sample.

In this problem, we have that:

Mean of 19 hours, standard deviation of 1.2 hours.

About 68.26% of the batteries failed between what two values?

This is within 1 standard deviation of the mean. So 68.2% of the batteries failed between 17.8 and 20.2 hours.

About 95.44% of the batteries failed between what two values?

This is within 2 standard deviations of the mean. So 95.44% of the batteries failed between 16.6 and 21.4 hours.

About 99.97% of the batteries failed between what two values?

This is within 3 standard deviations of the mean. So 99.97% of the batteries failed between 15.4 and 22.6 hours.

5 0
2 years ago
Read 2 more answers
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