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Marizza181 [45]
3 years ago
8

What volume (in L) of carbon dioxide will be produced from the reaction of 13.6 L of nitrogen monoxide?

Chemistry
2 answers:
VMariaS [17]3 years ago
7 0

Answer: 13.6

Explanation:

Korolek [52]3 years ago
6 0

Answer:

13.6

Explanation:

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a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is
NeX [460]

Answer:

The specific heat of iron is 0.45 J/g.°C

Explanation:

The amount of heat absorbed by the metal is given by:

heat = m x Sh x ΔT

From the data, we have:

heat = 180.8 J

mass = m = 22.44 g

ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C

Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT)  = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

8 0
3 years ago
The question is in the attached word document.
Alekssandra [29.7K]

Answer:i read it Explanation:

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3 years ago
I'm in a rush please help
Alexeev081 [22]

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4 0
4 years ago
Which statement best describes the light that will cause emission of electrons from a given metal through the photoelectric effe
Sergio039 [100]

Answer:

light with a high enough intensity

Explanation:

4 0
3 years ago
A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

7 0
3 years ago
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