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3 years ago

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Select the commonly used units of E.

2 answers:

ratelena [41]3 years ago

5 0

Answer:

electron volts

Kcal/mole

labwork [276]3 years ago

3 0

Assuming the E you are referring to is Internal Energy, <span>which refers to the total amount of the kinetic and potential </span>energies<span> of the particles that form your system. The common units for this internal energy are kcal/mole, and kJ/mol.</span>

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<span>Number of times the substituent group occurs is indicated by a prefix (di, tri, tetra, etc.</span>

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3 years ago

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(a) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm3. (b) A student needs 15.0 g of ethanol fo

o-na [289]

<u>Answer:</u>

<u>For a:</u> The density of the sample of copper is $8.96g/cm^3$

<u>For b:</u> The volume of ethanol needed is 19.0 mL

<u>For c:</u> The mass of mercury is 340. grams

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ ......(1)

<u>For a:</u>

Mass of copper = 374.5 g

Volume of copper = $41.8cm^3$

Putting values in equation 1, we get:

$\text{Density of copper}=\frac{374.5g}{41.8cm^3}\\\\\text{Density of copper}=8.96g/cm^3$

Hence, the density of the sample of copper is $8.96g/cm^3$

<u>For b:</u>

Mass of ethanol = 15.0 g

Density of ethanol = 0.789 g/mL

Putting values in equation 1, we get:

$0.789g/mL=\frac{15.0g}{\text{Volume of ethanol}}\\\\\text{Volume of ethanol}=\frac{15.0g}{0.789g/mL}=19.0mL$

Hence, the volume of ethanol needed is 19.0 mL

<u>For c:</u>

Volume of mercury = 25.0 mL

Density of mercury = 13.6 g/mL

Putting values in equation 1, we get:

$13.6g/mL=\frac{\text{Mass of mercury}}{25.0mL}\\\\\text{Mass of mercury}=(13.6g/mL\times 25.0mL)=340.g$

Hence, the mass of mercury is 340. grams

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3 years ago

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3 years ago

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