Solution :
Molar mass of
is :
M = 6×12 + 6×1 g
M = 78 g
78 gram of
contains
molecules.
So, 89.5 gram of
contains :
![n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}](https://tex.z-dn.net/?f=n%20%3D%206.022%20%5Ctimes%2010%5E%7B23%7D%20%5Ctimes%20%5Cdfrac%7B89.5%7D%7B78%7D%5C%5C%5C%5Cn%20%3D%206.91%20%5Ctimes%2010%5E%7B23%7D)
Now, from the formula we can see that one molecule of
contains 2 hydrogen atom . So, number of hydrogen atom are :
![h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms](https://tex.z-dn.net/?f=h%20%3D%202%5Ctimes%206.91%20%5Ctimes%2010%5E%7B23%7D%5C%5C%5C%5Ch%20%3D%201.38%20%5Ctimes%2010%5E%7B22%7D%5C%20atoms)
Hence, this is the required solution.
Answer:
Food and cell type
Explanation:
Kingdoms are by far the most basic legal structure for living objects. Living objects are classified into realms depending on how they consume food, the kinds of cells that produce their bodies, and the total type of tissue in their bodies.
Explanation:
I think 1) acidic solution
2) basic solution.
Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.
Explanation :
To calculate the percentage composition of element in sample, we use the equation:
![\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20element%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20element%7D%7D%7B%5Ctext%7BMass%20of%20sample%7D%7D%5Ctimes%20100)
Given:
Mass of carbon = 1.94 g
Mass of hydrogen = 0.48 g
Mass of sulfur = 2.58 g
First we have to calculate the mass of sample.
Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur
Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g
Now we have to calculate the percentage composition of a compound.
![\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20carbon%7D%3D%5Cfrac%7B1.94g%7D%7B5.0g%7D%5Ctimes%20100%3D38.8%5C%25)
![\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20hydrogen%7D%3D%5Cfrac%7B0.48g%7D%7B5.0g%7D%5Ctimes%20100%3D9.6%5C%25)
![\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20sulfur%7D%3D%5Cfrac%7B2.58g%7D%7B5.0g%7D%5Ctimes%20100%3D51.6%5C%25)
Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.