Question

A force of 3 pounds acts in the direction of 42 degrees to the horizontal. The force moves an object along a straight line from the point (3,7) to the point (8,8), with distance measured in feet. Find the work done by the force in foot-pounds.

Answer 1

Answer:

11.37 lb-ft

Step-by-step explanation:

We are given that

Force,F=3 pounds

$\theta=42^{\circ}$

Let Point  A (3,7)  and point B(8,8)

We have to find the work done by the force.

$d==$

$r=\mid d\mid=\sqrt{x^2+y^2}=\sqrt{5^2+1^2}=\sqrt{26}$ feet

We know that Work done by the force

$W=Frcos\theta$

Substitute the values

$W=3\times \sqrt{26}cos42=11.37 lb-ft$

Hence, the work done by the force =11.37 lb-ft