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velikii [3]
2 years ago
7

QUESTION 8

Mathematics
1 answer:
kotegsom [21]2 years ago
8 0

Answer:

no sé

Step-by-step explanation:

jajajajajajajajjajaa

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Someone please help me with this!!!
Dmitry_Shevchenko [17]

Answer:

it would be 3 85

Step-by-step explanation:

but rounded would be 3 100 pls mark as brainliest

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2 years ago
4/9+5/6 what is it?HELP!​
stiv31 [10]

Answer:

1 5/18

Step-by-step explanation:

4/9 = 8/18

5/6 = 15/18

15/18 + 8/18 = 23/18 = 1 and 5/18

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ser-zykov [4K]
2,350 Hope this helped
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3 years ago
Read 2 more answers
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
NEED ANSWER
STatiana [176]
C) sss similarity
because each side as a partner with half of its value
8in-4in
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