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Gnoma [55]
3 years ago
9

Tre has to pay $180 to book the recording studio plus $30 per hour of recording time. The function c(h)=30h+180 relates the tota

l cost, c(h) of the recording session (in dollars) to the number of hours, (h) needed to record the tracks.
Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

  • 1. $330
  • 2. 11.5 hours

Step-by-step explanation:

<u><em>Continuation of the question:</em></u>

  • <em>1. Find c (5) and interpret your solution in the context of the problem </em>
  • <em>2. Find the value of h when c() = 525 and interpret your solution in the context of the problem</em>

<u>Solution</u>

  • c(h) = 30h + 180

1 ...............................................

  • c(5) = 30*5 + 180 = $330

2 ...............................................

  • 525 = 30h + 180
  • 30h = 525 - 180
  • 30h = 345
  • h = 345/30
  • h = 11.5 hours

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3 years ago
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

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3 years ago
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3 years ago
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N2+40-28=
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3 years ago
On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she ha
Sveta_85 [38]

Answer:

a. P(X=50)= 0.36

b. P(X≤75) =  0.9

c. P(X>50)=  0.48

d. P(X<100) = 0.9

Step-by-step explanation:

The given data is

x                      25        50       75        100          Total

P(x)                0.16       0.36    0.38    0.10          1.00

Where X is the variable and P(X) = probabililty of that variable.

From the above

a. P(X=50)= 0.36

We add the probabilities of the variable below and equal to 75

b. P(X≤75) = 0.16+ 0.36+ 0.38= 0.9

We find the probability of the variable greater than 50 and add it.

c. P(X>50)= 0.38+0.10=  0.48

It can be calculated in two ways. One is to subtract the probability of 100 from total probability of 1. And the other is to add the probabilities of all the variables less than 100 . Both would give the same answer.

d. P(X<100)= 1- P(X=100)= 1-0.1= 0.9

8 0
3 years ago
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