the image and the pre-image are the same thing, which means that T and S are inverse operations.
<h3>How does the pre-image relate to the final image?</h3>
Here we have two transformations:
T(x, y) = (x + 3, y - 1)
S(x,y) = (x - 3, y + 1).
Now, let's start with a point (x, y), we will apply T first:
T(x, y) = (x + 3, y - 1)
Now our point is (x + 3, y - 1), and at that point, we apply the transformation S.
S(x + 3, y - 1) = (x + 3 - 3, y -1 + 1) = (x, y)
So the image and the preimage are the same thing, which means that T and S are inverse operations.
If you want to learn more about transformations:
brainly.com/question/4289712
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