It is given that, ABC BC =6.5cm CA=6.3cm AB=4.8cm Steps involved in construction Step 1: First draw a line segment AB = 4.8cm using pencil and ruler And mark one end A and other end B Step 2: From the point A draw an cm Step 3: From the point B draw an arc of length 6.5 cm Step point of intersection of these arc as C. Step 5: Join A and C & B and C. Now the triangle ABC is ready with BC =6.5cm CA=6.3cm AB=4.8cm
Answer:
I'm guessing it's D.
Step-by-step explanation:
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Answer:
Step-by-step explanation:
7) The formula for determining the area of a parallelogram is expressed as
Area = base × height.
Length of base = Area/height
Therefore,
Length of base = 7/2 = 3.5 feet
8) The formula for determining the area of a trapezoid is expressed as
Area = 1/2(a + b)h
Where
a and b are the length of the bases
h is the height. Therefore
21 = 1/2(2 + 4)h
21 = 3h
h = 21/3 = 7 inches
9) Area = base × height.
Height = Area/Length of base
Height = 28/14 = 2 inches
10) a and b are 10 inches each.
Area = 1/2(a + b)h
Therefore,
35 = 1/2(10 + 10)h
35 = 10h
h = 35/10
h = 3 inches
Im not positive but im pretty sure it's 27
Answer :
F-1(x)=-x/4-7/4
This is right
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