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3 years ago

Is it possible to have a triangle with two right angles? Explain your reasoning.

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

6 0

Answer and Explanation:

Because of the fact that the sum of the three interior angles of a triangle must be 180 degrees, a triangle could not have two right angles.

kifflom [539]3 years ago

6 0

Answer:

Step-by-step explanation:

For something to be considered a triangle, the sum of its angles must be 180 degrees. Right angles are 90 degrees. And since triangles must have 3 angles, it could not work. 80+80 exceeds 180.

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Can anyone help me solve these linear systems using substitution?

Andre45 [30]

Answer:

1. (2,2)

2. (-20, -1)

3. (4,3)

Step-by-step explanation:

See attached images

4 0

1 year ago

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Orlon Jewelry, a retail store, restructures its employees’ schedules every six months. The employees are asked for their shift p

natima [27]

Answer:

Step-by-step explanation:

Total sales:

Brian:

July, 38.9; August, 35.9, September, 40.5; October, 36.1

= $151,400

Laura:

July, 41.1; August, 36.8, September, 39.2; October, 43.3

= $160,400

Miguel:

July, 40.1; August, 44.1, September, 43.3; October, 39.7

= $167,200

Wanda:

July, 41.2; August, 36.5, September, 43.2; October, 39.3

= $160,200

Ranking:

1) Miguel (5 pm)

2) Laura (8 am)

3) Wanda (2 pm)

4) Brian (11 am)

6 0

2 years ago

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A single-engine plane is flying at 30 mph in the direction N 60° E. A wind is blowing from west to east at 15 mph

Ksivusya [100]

Answer:

C on Edge 2020

Step-by-step explanation:

The graph where the 60 degree angle is touching the y axis and air is above ground

7 0

2 years ago

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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

2 years ago

Factor completely. 2x^4+4x^3-30x^2

kramer

Answer:

Step-by-step explanation:

2x⁴ + 4x³ - 30x² = 2x²*(x² + 2x - 15)

x² + 2x - 15

Sum = 2

Product = -15

Factors = 5 ; (-3)

x² + 2x - 15 = x² + 5x - 3x - 3 *5

= x(x + 5) - 3(x + 5)

= (x + 5)(x - 3)

2x⁴ + 4x³ - 30x² = (2x²) (x + 5)(x - 3)

7 0

3 years ago