3 years ago

A partir de que materiales se obtienen los metales? en que se diferencian?

2 answers:

6 0

Los metales son materiales que se obtienen a partir de minerales que forman parte de las rocas. Por ejemplo, el metal hierro se extrae de minerales de hierro como la magnetita o la siderita.

GenaCL600 [577]3 years ago

5 0

ANSWER :No se esta pregunta

You might be interested in

Which of the following atoms would have the smallest atomic radius?

e-lub [12.9K]

Answer:

Lithuim is the smallest

Explanation:

i hope this helps!!

6 0

3 years ago

What category is most of the elements part of

rjkz [21]

Answer:

transition metals

Explanation:

they're the elements in yellow in the picture

6 0

3 years ago

Can you Answer the question below

tiny-mole [99]

The answer would be B

8 0

4 years ago

Elements in the same group (family) appeared to have the same what?

Radda [10]

I think it's D- Number of neutrons

3 0

4 years ago

What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O

nadya68 [22]

Answer:

$V=43.46mL$

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

$3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O$

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

$n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4$

Then, given the molarity, it is possible to obtain the milliliters as follows:

$V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL$

Best regards!

7 0

3 years ago