Explanation:
According to orbital hybridization theory, in ethene the C atoms are using sp2 hybrid orbitals. This leaves one unhybridized p orbital available to form the second bond (Pi bond) in the C-C double bonds.
One sp2 hybrid orbital from each C atom overlap to form one sigma bond between the two carbon atoms. One p orbital from each C atom then overlap to form a pi bond that completes the C-C double bond. The H atoms are bonded via sigma bonds to the C atoms when the H s orbitals overlap with the remaining sp2 hybrid orbitals from each C.
Pretty easy.. The ice is a solid, the rain is a liquid the drink is a liquid, the water drain is a liquid, the wood is a solid,
Answer:
Explanation:
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Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
![K=\frac{[NO_2]^2}{[NO]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BNO%5D%5E2%5BO_2%5D%7D)
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:
In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
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