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Oxana [17]
3 years ago
5

 121.6 G of water was brought to a boil(100°C) after having 23750 J of heat applied. If the specific heat of water is 4.18 J/G

°C, what was the initial temperature of the water?
A. 153.3°C
B. 46.7°C
C. 53.3°C
D. 146.7°C
Chemistry
1 answer:
Sergio [31]3 years ago
8 0

Answer: did you get the answer ?

Explanation:

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How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you
SOVA2 [1]

Explanation:

The given data is as follows.

        Concentration of solution = 0.5 M

        Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = \frac{\text{No. of moles}}{\text{Volume}}

Hence, calculate the number of moles as follows.

            No. of moles = Molarity × Volume

                                  = 0.5 M \times 1 L

                                  = 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

                                                      = 0.5 mol \times 132.119 g/mol

                                                      = 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0
3 years ago
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