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Oxana [17]
3 years ago
5

 121.6 G of water was brought to a boil(100°C) after having 23750 J of heat applied. If the specific heat of water is 4.18 J/G

°C, what was the initial temperature of the water?
A. 153.3°C
B. 46.7°C
C. 53.3°C
D. 146.7°C
Chemistry
1 answer:
Sergio [31]3 years ago
8 0

Answer: did you get the answer ?

Explanation:

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Can Hydrocyanic acid be a Lewis Acid? What about a Lewis Base?
FinnZ [79.3K]

HCN is a Bronsted acid; it can dissociate into H+ and CN-. And H+ is a Lewis acid because it accepts election pairs. ... In order for H+ and CN- to be formed, Hydrogen in HCN donates its electrons to Carbon. So in this sense, Hydrogen is the lewis base and Carbon is the lewis acid.

8 0
3 years ago
The ideal gas heat capacity of nitrogen varies with temperature. It is given by:
hammer [34]

Answer:

A)  1059 J/mol

B)  17,920 J/mol

Explanation:

Given that:

Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4

R (constant) = 8.314

We know that:

C_p=C_v+R

We can determine C_v from above if we make C_v the subject of the formula as:

C_v=C_p-R

C_V = 29.42-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4-8.314

C_V = 21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4

A).

The formula for calculating change in internal energy is given as:

dU=C_vdT

If we integrate above data into the equation; it implies that:

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4\,) du

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 1059J/mol

Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.

B).

If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.

then T = 273 K & T2 = 1073 K

∴

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})273/1+(5.82*10^{-7})1073/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 17,920 J/mol

3 0
4 years ago
Hydrocarbon mixtures are used as fuels.
Lunna [17]

The mass % of CH_4 in the mixture is <u>9.93%</u>

<h3>What are hydrocarbon?</h3>

An organic substance called a hydrocarbon is made completely of hydrogen and carbon. Group 14 hydrides include, for example, 620 hydrocarbons.

The odours of gasoline and lighter fluid serve as examples of the relatively weak or insignificant odours of hydrocarbons, which are often colourless and hydrophobic.

They can be found in a wide variety of chemical forms and phases, including gases (like methane and propane), liquids (like hexane and benzene), low melting point solids (like paraffin wax and naphthalene), and polymers (such as polyethylene and polystyrene).

In the context of the fossil fuel industries, the term "hydrocarbon" refers to petroleum, natural gas, and coal that are produced naturally, as well as to their hydrocarbon derivatives and refined forms. The primary source of energy for the entire planet is the burning of hydrocarbons.

Learn more about Hydrocarbon

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5 0
1 year ago
A block of metal has dimensions of 2 cm by 5 cm by 6 cm. The block weighs 780 g. From this information, calculate the mass, volu
adoni [48]

Answer:

mass = 78 grams

volume= 2*5*6=60cm^3

density =m/v

=78/60

13/10=1.3 g/cm^3

4 0
3 years ago
Which is a product in the following chemical reaction? CH4 + 2O2 → CO2 + 2H2O
NeX [460]
<span>CH4 + 2O2 → CO2 + 2H2O
</span>
The products are water (H2O) and carbon dioxide (CO2)
5 0
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