Answer:
False
Step-by-step explanation:
y=x-2 y=3x+4
Substitute the point into both equations and see if it is true
2=4-2
2=2 true
and
2=3*4+4
2 = 12+4
2 =16
False
It is not a solution
The correct answer is 4a^2 + 3ab
In order to find this, we can write the equation out as described and then follow the order of operations.
3a^2 - 2ab + 3b^2 - (-a^2 - 5ab + 3b^2) ----> Distribute the negative
3a^2 - 2ab + 3b^2 + a^2 + 5ab - 3b^2 ----> Combine like terms
4a^2 + 3ab
Answer:
(2,14)
Step-by-step explanation:
so i solved this with substitution but there are other methods to solve this!
equation 1 : y = -x + 16
equation 2 : y = x + 12
solve for y in equation 1 !!
y = -x + 16
(add x on both sides)
y + x = 16
(subtract y on both sides)
x = -y + 16
equation 1 now equals : x = -y + 16
substitute equation 1 into equation 2 :)
y = (-y + 16) + 12
(add 16 + 12)
y = -y + 28
(add y on both sides)
2y = 28
(divide 2 on both sides)
y = 14
now to solve for x you can insert y !
you can use equation 1 or equation 2 to solve for x.
i'm using equation 2 :
y = x + 12
(14) = x + 12
(subtract 12 on both sides)
x = 2
therefore, the answer is (2, 14).
hope this helps :p
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Answer:
D: 216 E: 2038
Step-by-step explanation:
For D:
P= - 55/4 × t + 340
Substitute in for t (2022-2013=9)
-55/4 × 9 = - 123.75
-123.75+340= 216.25
Round down to 216
For E:
The owl population =0
0=-55/4×t+340
-340=-55/4 × t
-340÷-55/4=t
T=24.7272
Round to 25
25+2013 =2038