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cluponka [151]
3 years ago
11

Find the perimeter of a rectangle if one of its sides is 14 and the area is 98

Mathematics
1 answer:
Ratling [72]3 years ago
7 0

Answer:

42

Step-by-step explanation:

Area of a rectange = bh so 98=14x

98 divided by 14 = 7

Perimeter= 2x+2y

so 2x+2y -> 28+14=42

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The length of a rectangular field is 30 more than twice it’s width write an expression in simplest form for the perimeter of the
Verizon [17]
L= 2w+30

Perimeter= 2(l+w)
Substitute in the length above
P=2 ((2w+30) + w)
Remember order of operations. You must multiply everything by 2 before adding.
P=4w+60+2w
P=6w+60
5 0
4 years ago
An art history professor assigns letter grades on a test according to the following scheme. A: Top 13%13% of scores B: Scores be
amm1812

Answer:

The numerical limits for a B grade is between 81 and 89.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

Below the top 13%:

Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So

Z = \frac{X - \mu}{\sigma}

1.127 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*1.127

X = 89

Above the bottom 56:

Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 8.4*0.15

X = 81

The numerical limits for a B grade is between 81 and 89.

3 0
3 years ago
The recommended storage temperature for a certain type of squash is 10°C to 13°C. Which inequality
noname [10]

Answer:

The simultaneous inequation representing the recomended storage temperature is:

50\,^{\circ}F \leq T \leq 55.4\,^{\circ}F

Step-by-step explanation:

In this case, the statement must be represented mathematically by a simultaneous inequation, in which temperature must be equal to or greater than 10 ºC, expressed in Fahreheit degrees, and equal or less than 13 ºC, expressed in Fahrenheit degrees.

Bounds can be converted into Fahrenheit degrees from Celsius degrees:

T_{F} = \frac{9}{5} \cdot T_{C}+32\,^{\circ}F (Eq. 1)

Where:

T_{C} - Temperature, measured in Celsius degrees.

T_{F} - Temperature, measured in Fahrenheit degrees.

Lower bound (T_{C} = 10\,^{\circ}C)

T_{F} = \frac{9}{5}\cdot (10\,^{\circ}C) + 32\,^{\circ}F

T_{F} = 50\,^{\circ}F

Upper bound (T_{C} = 13\,^{\circ}C)

T_{F} = \frac{9}{5}\cdot (13\,^{\circ}C) + 32\,^{\circ}F

T_{F} = 55.4\,^{\circ}F

The simultaneous inequation representing the recomended storage temperature is:

50\,^{\circ}F \leq T \leq 55.4\,^{\circ}F

6 0
3 years ago
What do you do to get this answer and what is the answer
Amanda [17]

Here is your answer

Convert the mixed fraction into into improper fraction.

7\frac{1}{5} × 2 \frac{1}{6}

= \frac{36}{5} × \frac{13}{6}

=\frac{6×13}{5}

=\frac{78}{5}

=15\frac{3}{5}

HOPE IT IS USEFUL

7 0
3 years ago
PLEASE HELP ITS URGENT
Sveta_85 [38]
X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)

Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.
6 0
4 years ago
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