Are these lines parallel, perpendicular, or neither? 3y=x+4 and 3x+y=1

Mathematics

2 answers:

Goryan [66]3 years ago

6 0

Answer:

These lines are perpendicular

Step-by-step explanation:

3y=x+4

$y = \frac{1}{3}x+\frac{4}{3}$

Slope (m1) = 1/3

3x+y=1

y = -3x + 1

Slope (m2) = - 3

m1 * m2 = $\frac{1}{3}* -3$

= -1

So, these lines are perpendicular.

If product of two slopes is (-1), then they are perpendicular lines.

If both lines have same slope, then they are parallel.

REY [17]3 years ago

5 0

Answer:

perpendicular

Step-by-step explanation:

3y = x + 4 in slope intercept form y = 1/3x +4/3

3x + y = 1 in slope intercept form y = -3x +1

the slopes are negative reciprocals of each other so they are perpendicular

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