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kifflom [539]
2 years ago
6

Are these lines parallel, perpendicular, or neither? 3y=x+4 and 3x+y=1

Mathematics
2 answers:
Goryan [66]2 years ago
6 0

Answer:

These lines are perpendicular

Step-by-step explanation:

3y=x+4

 y = \frac{1}{3}x+\frac{4}{3}

Slope (m1) = 1/3

3x+y=1

     y = -3x + 1

Slope (m2) = - 3

m1 * m2 = \frac{1}{3}* -3

             = -1

So, these lines are perpendicular.

If product of two slopes is (-1), then they are perpendicular lines.

If both lines have same slope, then they are parallel.

REY [17]2 years ago
5 0

Answer:

perpendicular

Step-by-step explanation:

3y = x + 4 in slope intercept form y = 1/3x +4/3

3x + y = 1 in slope intercept form y = -3x +1

the slopes are negative reciprocals of each other so they are perpendicular

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Look at the graph picture I attached

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to find where it crosses the x-axis, we make y = 0

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SIZIF [17.4K]
0.10d + 0.25q = 3.55
q = d + 3

0.10d + 0.25(d + 3) = 3.55
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