Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.
For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.
<h3>Binomial probability distribution
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The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- One in ten students are named Joe, hence
.
- There are 15 students in the class, hence
.
The probability that at least one of them is named Joe is:
In which:
Then:
0.7941 = 79.41% probability that at least one of them is named Joe.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
4 months
Step-by-step explanation:
Franco's provider = 60 + 42.95x
Marshal's provider = 57.95x
Where,
x = number of months
Equate both charges
Franco's provider = Marshal's provider
60 + 42.95x = 57.95x
Subtract 42.95x From both sides
60 + 42.95x - 42.95x = 57.95x - 42.95x
60 = 15x
Divide both sides by 15
60 / 15 = 15x / 15
4 = x
x = 4 Months
Franco and Marshal would have paid the same amount for high-speed Internet service after 4 months
First, write out the statement as an inequality so that it looks like this: x<span>≤11/5
Then you graph it on a number line, and since you know anything greater/less than or equal to is a closed circle since it includes the value 11/5, you would plot a closed circle on 11/5 on a number line and draw and arrow pointing towards the left to show that only values 11/5 or under can satisfy x.
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Answer:
Option D
Step-by-step explanation:
Option A:
(3)¹ × (3)⁻¹⁰ = (3)⁽¹⁻¹⁰⁾ = 3⁹
= 
= 
Option B :
(3)⁻¹ × (3) ¹⁰ = 3⁽¹⁰⁻¹⁾
= 3⁹
= 19683
Option C :
(3⁻⁴) × (3)⁷ = 3⁽⁷⁻⁴⁾
= 3³
Option D :
3⁴ × 3⁻⁷ = 3⁴⁻⁷
= 3⁻³
= 
= 
Therefore, option D is the answer.
Answer:
3:2
Step-by-step explanation:
