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cluponka [151]
3 years ago
13

Construct a tangent to a circle through a point on the circle using the construction tool. Insert a screenshot of the constructi

on below. Leave all circle and arc markings. (10 points)
Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

Refer to the attachment \Huge{\blue{\nearrow}}

Step-by-step explanation:

<h3><u>Diagram</u><u>:</u><u>-</u></h3>

\setlength{\unitlength}{1.1mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\put(25,30){\line(1,3){6.4}}\put(25,30){\line(1, - 3){6.4}}\put(20,7){\line(3,1){68.5}}\put(20,52.8){\line(3, - 1){68.5}}\put(25,30){\circle*{1}}\put(88,30){\circle*{1.2}}\put(22,30){\sf O}\put(31,6){\sf A}\put(31,52){\sf B}\put(90,28.5){\sf P}\multiput(25,30)(3,0){21}{\line(2,0){1.8}}\qbezier(81.5,32)(78,30)(81,27.5)\qbezier(76,30)(74.5,28)(76,26)\put(33,45){\line(1,3){1.1}}\put(30,45.8){\line(3, - 1){3.2}}\put(30.5,14){\line(3,1){3.2}}\put(33.5,15){\line(1, - 3){1.1}}\put(21,18){\sf 6 cm}\put(73,30.8){\sf 120^\circ$}\put(69,26){\sf 60^\circ$}\end{picture}

<h3><u>Note</u><u>:</u><u>-</u></h3>

View the ans from Web for complete diagram.

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A father is 25 years older than his son. 10 years ago, he was six times as old his son. What are their present ages?​
RoseWind [281]

Answer:

Present age of son = 15 years

& Present age of father = 40 years

Step-by-step explanation:

  • Let the son's present age be x years

  • -> Father's present age = (x + 25) years

  • 10 years ago:
  • Son's age = (x - 10) years

  • Father's age = (x +25 -10) = (x +15) years

  • It is given that: 10 years ago father was six times as old as his son

  • -> x + 15 = 6(x - 10)

  • -> x + 15 = 6x - 60

  • -> x- 6x = - 60 -15

  • -> -5x = - 75

  • -> x = -75/(-5)

  • -> x = 15

  • -> x + 25 = 15 + 25 = 40

  • -> Present age of son = 15 years

  • & Present age of father = 40 years.
3 0
2 years ago
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Answer: C

Step-by-step explanation:

3 0
2 years ago
A dependent system of equations is a system with<br> the same line
Naddik [55]
I don’t understand your question
4 0
2 years ago
George jogged downhill at 6 mph and then jogged back up at 4 mph. If the total jogging time was 1.25 hours, how far did he jog i
Anna35 [415]

The total distance covered is 6 m

<u>Step-by-step explanation:</u>

Let the total distance be '2d'

Total time = 1.25hrs

Downhill speed = 6 mphr

Uphill speed = 4 mphr

(d/6) +(d/4) = 1.25

(2d + 3d) /12 = 1.25

5d/12 = 1.25

d = 3m

So, 2d = 6 m

The total distance covered is 6 m

7 0
3 years ago
Spend some time looking at the vehicles on the road. Look at the first 40 vehicles that drive by. Take note of the number of veh
Brilliant_brown [7]

Answer:

The confidence interval is ( 0.225952516, 0.474047484)

People will get different results because, the amount of sedans may be dependent on the area in which the data is taken.

No, the sample is not really a good representation of the whole population of vehicles, since only a certain area was sampled or experimented.

Step-by-step explanation:

Solution

Given that:

From the experiment we discovered that out of 40 vehicles, 14 of them were sedans.

Let us note that:

p^ = It is the point estimate of the population proportion

Where,

n=/n  = 0.35

We also check for the standard error of p, sp:

which is,

sp =√{p^ (1-p^)/n] =0.075415516

Thus,

for the the critical z, we have the following:

α/2 = 0.05

So,

z (α)/2 = 1.644853627

Thus,

For lower bound = p^ - z(α/2) * sp = 0.225952516

For upper bound = p^ + z(α/2)* sp = 0.474047484

Hence,

The confidence interval becomes: ( 0.225952516, 0.474047484)

8 0
3 years ago
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