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sergiy2304 [10]
2 years ago
10

If sin(A - 30) = cos 60°, the number of degrees in the measure of angle A is

Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:1

Step-by-step explanation:

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What two formulas are necessary to find the area of a segment of a circle?
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Answer:

Step-by-step explanation:

Area of a Segment in Radians A = (½) × r2 (θ – Sin θ)

Area of a Segment in Degrees A = (½) × r 2 × [(π/180) θ – sin θ]

3 0
2 years ago
Please help. I don't need a big explanation just a answer
stiv31 [10]
A answer of the explanation for the explanation is the answer
6 0
3 years ago
Plz with steps .. it's very hard can anyone plz
liubo4ka [24]

Answer:

Step-by-step explanation:

\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a}  \qquad  f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a}  \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}}  }{\dfrac{1}{2\sqrt{x}} }\\\\

\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}  =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\

7 0
3 years ago
Exact coordinates of either on this circle whose x-coordinates is 5.​
olga2289 [7]

Answer:

hope it helps plz mark me brainliest..

Step-by-step explanation:

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What does solution to the division mean and what does it tell you
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