1/2 × 5 2/3 × 3 = 5
the 2's cancel giving you 5 × 1/3 × 3
then the 3's cancel giving you 5 × 1
and 5 × 1 is 5.
Answer:
a) shown
b) h = [sqrt(17) - (5/2)t]²
c) t = 2sqrt(17)/5 seconds
Step-by-step explanation:
V = pi × r² × h
V = pi × 5² × h
V = 25pi × h
a) dV/dt = dV/dh × dh/dt
-5pi × sqrt(h) = 25pi × dh/dt
dh/dt = -sqrt(h)/5
b) 1/sqrt(h) .dh = -5. dt
2sqrt(h) = -5t + c
t = 0, h = 17
2sqrt(17) = 0 + c
c = 2sqrt(17)
2sqrt(h) = -5t + 2sqrt(17)
sqrt(h) = [2sqrt(17) - 5t] ÷ 2
sqrt(h) = sqrt(17) - (5/2)t
Square both sides
h = [sqrt(17) - (5/2)t]²
c) empty: h = 0
0 = [sqrt(17) - (5/2)t]²
sqrt(17) - (5/2)t = 0
(5/2)t = sqrt(17)
t = 2sqrt(17)/5
t = 1.64924225 seconds
sqrt: square root
Answer:
D. 6x2 + 3x - 7
Step-by-step explanation:
18 - (8 - 3 • (2t + 5)) = 0
6t + 25 = 0
3.1 Solve : 6t+25 = 0
Subtract 25 from both sides of the equation :
6t = -25
Divide both sides of the equation by 6:
t = -25/6 = -4.167
Final answer is
t = -25/6 = -4.167
I got 6x+3
The three equations are:
(2x-6) + (3x+1) + (x+8) =perimeter
2x+3x+x/1x=6x
-6+1+8= 3
