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AfilCa [17]
2 years ago
5

15% of the seats on an airplane are first class if there are 24 class seats how many seats are on the plane ​

Mathematics
1 answer:
Andrej [43]2 years ago
6 0

Answer:

160

Step-by-step explanation:

there are 24 first class seats. 15% of the total number is 24. that would mean 5% of the total number is 8. 20 times 8 is 160.

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Madison saves 40% of all that she earns for washing cars. So far she has saved $72 . How much has she earned in all?
UkoKoshka [18]

Answer:

40% = 72

divide both sides by 40 to find 1%

1% = 1.8

now multiply by 100 to find total amount earned

100% = 180

total earned $180

7 0
3 years ago
The circle below is centered at the point (-1,3) and has a radius of length 4
Snowcat [4.5K]
(x-h)^2 + (y-k)^2 = r^2 where h & k are the x,y values of the center point

(x + 1)^2 + (y-3)^2 = 4^2
<span>(x + 1)^2 + (y-3)^2 = 16</span>
6 0
3 years ago
Find the x is qs bisects pqr and pqr=82
slavikrds [6]

if ∡PQR = 82°, and the ray QS bisects it, it cuts ∡PQR into two equal halves, ∡PQS and ∡RQS, each of which is then 82/2, or 41°.


\bf \stackrel{\measuredangle PQS}{10x+1}=41\implies 10x=40\implies x=\cfrac{40}{10}\implies x=4

5 0
3 years ago
Read 3 more answers
If b= 7, what is 1/3(2b+10)? Please help
goblinko [34]

Answer:8

Step-by-step explanation:

First, substitute 7 into the equation for b:

1/3(2x7+10)

Now, simplify using the order of operations:

1/3(14+10)

Then:

1/3 (24)

And you arrive at your answer:

8

3 0
3 years ago
Read 2 more answers
Mark signed an appointment to receive internet service on his mobile phone for the service he pays a monthly fee plus a charge f
FinnZ [79.3K]

Answer:

<em>Mark used 6.43 megabytes of data.</em>

Step-by-step explanation:

The given equation is:   5.25+0.3m=7.18 , where m is amount of data used in megabyte.

For finding the amount of data Mark used, <u>we need to solve the above equation for m</u>.

First subtracting 5.25 from both sides, we will get.....

5.25+0.3m-5.25= 7.18-5.25\\ \\ 0.3m=1.93

Now, dividing both sides by 0.3 ...........

m=\frac{1.93}{0.3}=6.4333... \approx 6.43

<em>(Rounded to the nearest hundredth)</em>

Thus, Mark used 6.43 megabytes of data.

3 0
3 years ago
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