First, we need to transform km to meters.
1 km = 1000 meters
2.6 * 1000 = 2600
Now, there are 7 days in a week.
Multiply.
2600 * 7 = 18,200
Final answer: 18,200 meters a week
Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen
if it occupies 31.6 mL at
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.

Temperature = 
As molar mass of
is 32 g/mol. Hence, the number of moles of
are calculated as follows.

Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen
if it occupies 31.6 mL at
.
an atom will gain or lose electrons to obtain 8 electrons in it's outer shell. In other words, elements want to reach an electron configuration of the nearest noble gas.
Answer:
Potassium permanganate.
Explanation:
Both substances are dyes, but the methylene blue has a bigger molecular mass (319.85 g/mol), that means that the particles are bigger in comparison with the potassium permanganate that has a molecular mass of 158.034 g/mol.
Since the molar mass is the half in the case of potassium permanganate, it can be considered that the particle size is the half in size. In the agar, a smaller particle will present less resistance to flow, that means that it going to move faster.
Answer: 3378.4mL
Explanation:
density of Gasoline = 0.74g/mL.
Volume of gasoline in milliliter = ?
mass of gasoline = 2.5kg
(Since density is in grams per millilitre, convert mass in kilograms to grams)
If 1kg = 1000grams
2.5kg = 2.5 x 1000 = 2500grams
Recall that density is obtained by dividing the mass of a substance by its volume
i.e Density = Mass / Volume
0.74g/mL = 2500grams/Volume
Volume = (2500 grams / 0.74g/mL)
Volume = 3378.4mL
Thus, the volume of gasoline is 3378.4mL