<span>ANSWER:
Organic reactions proceed at a very SLOWER rate.
Reasoning:
</span><span>Organic reactions are chemical reactions involving organic compounds. They are less soluble</span> in water than inorganic compounds. Therefore, organic compounds react at a slower rate and produce a much more complex set of products than inorganic compounds.
Answer: 48,501 J/mol
Explanation:
1) Action barrier = activation energy = Ea
2) Data:
i) T₁ = 12°C = 12 + 273.15 K = 285.15K
ii) T₂ = 22°C = 22 + 273.15 K = 295.15 K
iii) rate constant = k: k₂ / k₁ = 2
iv) Ea = ?
3) Formula:
Arrhenius' law gives the relationship between the constant of reaction and the temperature:

4) Solution
By arranging the formula, you get:
㏑[k₂/k₁] =Ea/R [1/T₁ - 1/T₂]
Replace k₂ = 2k₁; T₁ = 285.15; and T₂ = 295.15
ln[2] = Ea/8.314 J/K mol × [1/285.15 - 1/295.15]K
Ea = ln [2] × 8.314 J/K mol / [1.18818×10⁻⁴K] = 48,501 J/mol
A base generally releases a hydroxide ion (OH-) when dissolved in water.
There are exceptions, such as ammonia NH3, which acts as a base but does not produce OH- ions. There are three definitions of acids and bases (Arrhenius, Bronsted-Lowry, and Lewis) and each one looks at acid/base characteristics differently. OH- donation is the Arrhenius definition.
The electrons fill energy levels from the lowest available energy level, based of three typical rules.
1) Follow Aufbau rule: fill from lower to higher energy levels (1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p)
2) Pauly exclusion principle: two electrons can not have the same four quantum numbers
3) Hund rule: if the orbitals have the same energy, the electrons must go to different orbitals before two occupies the same orbital.
<u>step</u><u> </u><u>by</u><u> </u><u>step</u>
Na(sodium)=2.8.1
Cl (Chlorine)=2.8.7. sodium will give the chlorine the 1 valence electron to become stable ions.
<u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>
<u>p</u><u>o</u><u>t</u><u>t</u><u>a</u><u>s</u><u>i</u><u>u</u><u>m</u><u>. </u><u>(</u><u>2</u><u>.</u><u>8</u><u>.</u><u>8</u><u>.</u><u>1</u><u>)</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>F</u><u>l</u><u>o</u><u>u</u><u>r</u><u>i</u><u>n</u><u>e</u><u>(</u><u>2</u><u>.</u><u>7</u><u>)</u>