Answer:
Moles of carbon dioxide are 1.57
Explanation:
Using ideal gas law, you can find moles of a gas with its pressure, temperature and volume, thus:
PV = nRT
PV/RT = n
<em>Where P is pressure, V is volume (35.2L); R is gas constant (0.082atmL/molK); T is absolute temperature and n are moles</em>
At STP, temperature is 273.15K and pressure is 1atm
Replacing:
1atm×35.2L / 0.082atmL/molK×273.15K = n
<em>1.57 = n</em>
<em>Moles of carbon dioxide are 1.57</em>
<em>mC: 12g/mol</em>
12g ------- 6,02·10²³ a.
6g --------- X
X = (6×<span>6,02·10²³)/12
</span><u>X = 3,01·10²³ atoms</u>
---->>> A :)
Answer:
numero de oxidacion: 3+2+2-3
Explanation:
