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jeyben [28]
2 years ago
12

Write each as a fraction ​

Mathematics
2 answers:
Zina [86]2 years ago
6 0

Answer:

18) 7/10 20) 58/100 or 29/50 22) 2/3 24) 8/10 or 4/5 26) 3/10

Step-by-step explanation:

Pavel [41]2 years ago
6 0

Answer:

18. 7/10 20. 29/50 24. 4/5 26. 3/10

Step-by-step explanation:

Umm im sorry i cant find number 22

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Dddddddddddddddddddddddd
Ierofanga [76]

Answer:

dddddddddddddddddddddddd could be rewritten as d^24 because d*d*d*d*d*d*d... = d^24

Step-by-step explanation:

When we multiply all of the d's together we get d^{24}.

4 0
3 years ago
Read 2 more answers
Please help me solve the expression for “n”
Bingel [31]

Answer:

  n = 2

Step-by-step explanation:

In order for the ratio to have a value of 1, the sum of exponents in the numerator must equal the sum of exponents in the denominator:

  n + 7 = 9

  n = 9 -7 . . . . . . subtract 7 from both sides of the equation

  n = 2

___

Alternatively, you can simplify the given expression:

  \dfrac{9^n(9^7)}{9^9}=1=\dfrac{9^n}{9^2}

Hopefully, it is clear to you that the value of n must be 2 in order to make the numerator equal to the denominator.

5 0
2 years ago
T: 3(t + 3) + 5(3 + 2t) – 76 = 0
Setler [38]

Answer:

\huge\boxed{\sf t = 4}

Step-by-step explanation:

\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
Read 2 more answers
What is the value tan a ????
stich3 [128]

Where is this picture ?

5 0
3 years ago
Simply as far as possible<br> 3root3(2root2+2root3)
Lerok [7]

Answer:

3 \sqrt{3} \:  (2 \sqrt{2}  + 2 \sqrt{3} ) \\ (3 \sqrt{3}  \times 2 \sqrt{2})  + (3 \sqrt{3}  \times 2 \sqrt{3} ) \\  \\ 6 (\sqrt{3}  \times  \sqrt{2}  )+ 6 ( \sqrt{3}  \times  \sqrt{3} ) \\  \\ 6 \sqrt{6}  + 6(3) \\  \\ =  6 \sqrt{6}  + 18  \\  \\ 6(2.449) + 18 \\  \\  14.694 + 18 \\  \\  = 32.694

I hope I helped you^_^

7 0
2 years ago
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