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mote1985 [20]
3 years ago
9

Assume that a company cannot determine the market value of equipment acquired by reference to a similar purchase for cash. Expla

in how the company determines the cost of equipment purchased by exchanging it for each of the following 3 items: Bonds having an established market price. Bonds that do not have an established market price. Common stock not having an established market price. Similar equipment having a determinable market value.
Business
1 answer:
Ghella [55]3 years ago
8 0

Solution :

Let us suppose that a company cannot predict the market value of an equipment that acquired by the reference to the similar purchase for the cash. Thus the company finds cost of purchased of the equipment by exchanging :

-- the market price of the bonds when they have an established price in the market.

-- the market price of the bonds when the common stocks does not have a established market price.

-- market price of the equipment when the similar kind of an equipment have a determinable value in the market.

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It is also called improvement taxes.

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If you have 4.00 gg of H2, how many grams of NH3 can be produced?
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Answer:

22.49 g of NH3

Explanation:

The balanced equation for this would be:

3H₂+N₂ → 2NH₃

So let's take note of this:

We will need 3 moles of H₂ to produce 2 moles of NH₃.

Now let us convert:

First we determine the molar mass of H2:

Element:

     number of atoms   x     molar mass

H   =          2                 x       1.01 g/mol = 2.02 g/mol

Let's see how many moles of H2 there are in 4.00g

4.00 g\times \dfrac{1\;mole\;of\;H_2}{2.02g} = 1.98\;moles\;of\;H_2

Now we can see how many moles of NH₃ we can make given the ratio and convert it again to grams by getting the molar mass of NH₃:

1.98\;moles\;of\;H_2\times\dfrac{2\;moles\;of\;NH_3}{3\;moles\;of\;H_2} = 1.32\;moles\;of\;NH_3

This means that with 1.98 moles of H₂, we produce 1.32 moles of NH₃

So let's get the molar mass of NH₃ so we can convert it to grams:

N      =   1 x 14.01 = 14.01

H      =  3 x 1.01   = 3.03

                             17.04g/mol

1.32\;moles\;of\;NH_3\times\dfrac{17.04g\;of\;NH_3}{1\;mole\;of\;NH_3} = 22.49g\;of\;NH_3

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The direct write-off method records bad debt expense only when an account becomes uncollectible, which is not always in the same
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