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Eddi Din [679]
3 years ago
8

Which one is not an ore of copper

Chemistry
1 answer:
Contact [7]3 years ago
6 0
Answer: malachite!!!!

hope this helps!
You might be interested in
Which formula demonstrates a double replacement reaction?
olga_2 [115]

Answer:

2

Explanation:

8 0
3 years ago
If an individual proton has mass 1.007825 amu, and an individual neutron has mass 1.008665 amu, what's the calculated mass of a
german

Answer:

C) 237.96682 amu

Explanation:

The symbol for neptunium-236 is given as;

²³⁶₉₃Np

This element has 93 protons and (236 - 93 = 143) neutrons.

Mass Number =Total mass of Protons + Total mass of neutrons

Total Mass pf protons = 93 * 1.007825 amu, = 93.727725 amu

Total mass of Neutrons = 143 * 1.008665 amu = 144.239095 amu

Mass = 144.239095 + 93.727725  = 237.96682 amu

Correct option is option C.

7 0
3 years ago
Calculate the density of a sample if the mass is 2.98g and the volume is 2.12l
sineoko [7]
Hey there!:

Mass = 2.98 g

Volume = 2.12 L

Therefore:

Density = mass / volume

Density = 2.98 / 2.12

Density = 1.405 g/L
6 0
4 years ago
During a laboratory experiment you discover that an enzyme-catalyzed reaction has a delta G of -20 kcal/mol. If you double the a
Ilia_Sergeevich [38]

Answer:

-20 kcal/mol

Explanation:

In a reaction, enzymes reduces the energy of activation, but they have no effect on the Gibb's free energy of reaction. The free energy of the product is the same as it would be without the enzyme. Thus, the enzyme does not affect the free energy of the reaction. Mathematically

Gibb free energy = Enthalpy - temperature x change in entropy

Note that from the relation above, enzyme is not a factor nor is activation energy a factor.

3 0
3 years ago
What is the mass of 2.53x10^34 atoms of Ni?
LUCKY_DIMON [66]

Answer:

2.48 g

Explanation:

From the question given above, the following data were obtained:

Number of atoms = 2.53×10³⁴ atoms

Mass of Ni =?

From Avogadro's hypothesis,

we understood that 1 mole of any substance contains 6.02×10²³ atoms.

Therefore, 1 mole of Ni contains 6.02×10²³ atoms.

Recall:

1 mole Ni = 59 g

Therefore, 59 g of Ni contains 6.02×10²³ atoms.

Finally, we shall determine the mass of 2.53×10³⁴ atoms of Ni. This can be obtained as follow:

6.02×10²³ atoms = 59 g

Therefore,

2.53×10³⁴ = 2.53×10³⁴ × 59 / 6.02×10²³

2.53×10³⁴ atoms = 2.48 g

Thus, the mass of 2.53×10³⁴ atoms of Ni is 2.48 g.

8 0
3 years ago
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