Suppose you wanted to dissolve 106 g of Na2CO3 in enough H2O to make 6.00 L of solution.

Chemistry

2 answers:

Bezzdna [24]3 years ago

6 0

Molar mass of Sodium Carbonate is 106, molarity is 1.0M. Seriously just look at a periodic table this is easy stuff.

FinnZ [79.3K]3 years ago

4 0

M(Na2CO3)=2M(Na)+M(C)+3M(O)
=2(23)+12+3(16)
=46+12+48
=106 g/mol
the molar mass of Na2CO3 is 106 g/mol
m=106g M=106 g/mol n=m/M
n=m/M n=106/106 n=1mol

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3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.

tiny-mole [99]

Answer:

The Avogadro's number is $N_A = 6.02289 *10^{23}$

Explanation:

From the question we are told that

The edge length is $L = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100} = 5.02 * 10^{-10}$

The density of the metal is $\rho = 5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3} * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3$

The molar mass of Ba is $Z = 137.3 \ g/mol = \frac{137.3}{1000} = 0.1373 \ kg / mol$

Generally the volume of a unit cell is

$V = L^3$

substituting value

$V = [5.02 *10^{-10}]^3$

$V = 1.265*10^{-28}\ m^3$

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be (BCC),

The volume of barium atom is

$V_a = \frac{V}{2} * 0.68$