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Chemistry

1 answer:

katen-ka-za [31]4 years ago

5 0

The answer is compound

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Consider these compounds:

Afina-wow [57]

Answer:

Without doing any calculations it is possible to determine that silver chromate is more soluble than C,D , and silver chromate is less soluble than none .

It is not possible to determine whether silver chromate is more or less soluble than A,B by simply comparing Kspvalues

Explanation:

For this kind of question you need to obtain the balanced equation for the solubility, first, you will write the dissociation equation for every molecule, obtaining the ions in which it dissociates. Then you substitute in the Kps equation

$A_{n}B_{m} -> nA^{m+}+mB^{n-} \\K_{s}=[A^{m}]^{n}[B^{n}]^{m}$

Considering the corresponding stoichiometry you'll substitute in your dissociation equations as follow.

$Ag_{2}CrO_{4}(s)->2Ag^{+}(aq)+CrO_{4} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\A) PbF_{2}(s)->Pb^{2+} (aq)+2F^{-}\\s->s+2s\\s->[s][2s]^{2}=4s^{3}\\\\\\B)Ag_{2}SO_{3}(s)->2Ag^{+}(aq)+SO_{3} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\\\C)NiCO_{3}(s)->Ni^{2+}(aq)+CO_{3} ^{2-}\\ s ->s+s\\s->[s][s]=s^{2} \\\\\\D)AgCl(s)->Ag^{+}(aq)+Cl^{-}(aq)\\ s ->s+s\\s->[s][s]=s^{2} \\$

IIn this case, the silver chromate has a Kps of $4sx^{3}$ , same as the compound in options A and B, comparing these numbers you can't determine which one is bigger. Finally, options C and D have a kps of $s^{2}$ , this value is smaller than silver chromate's kps.

I hope you find this information useful! good luck!

7 0

3 years ago

SOMEONE PLEASE HELP! IVE BEEN STUCK ON THIS QUESTION FOR AN HOUR

Maslowich

I believe it’s the Distance Traveled that is the dependent variable, because the smooth wood, rough wood and number of students are all fixed. I’m not sure though! I hope this helps.

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3 years ago

Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?

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