Blank + 3.7 = 1 what is the blank

Mathematics

1 answer:

tangare [24]3 years ago

7 0

Answer:

-2.7

Step-by-step explanation:

really dude

You might be interested in

If I roll two six-sides dice, what is the probability that the sum of the numbers that show up on the dice is 3 or less?

liq [111]

Answer:

1/12

Step-by-step explanation:

first we have to find all the possibilities of getting a sum of 3 or less: 1+1 or 1+2 and we count the second combination 2 times because the numbers can be on either of the dices so we have a total of 3 possibilities. all the possible pairimg of dice are 6*6=36 because each dice has 6 sides and we can get either of them. so the probability would be the chance of getting a sum of 3 or less divided by all the diff combination which equals 3/36 or 1/12 which is roughly around 8.3%

4 0

3 years ago

a quadratic equation has a discriminant of 12. which could be the equation? a.0 = –x2 8x 2 b.0 = 2x2 6x 3 c.0 = –x2 4x 1 d.0 = 4

Norma-Jean [14]

Answer:

Option b which is $2x^2+6x+3=0$

Step-by-step explanation:

We have been given the discriminant 12

We have to choose the equation which will satisfy the given discriminant.

We will consider all the given equation one by one

First we will take option a which is $-x^2+8x+2=0$

Discriminant from the equation we will find by the formula

$D=b^2-4ac$

Here, a=-1,b=8 and c=2 on substituting the values we will get

$D=8^2-4(-1)(2)=72$

Hence, option a is incorrect.

Now, we will consider option b which is $2x^2+6x+3=0$

Here, a=2,b=6 and c=3 on substituting the values we get

$D=(6)^2-4(2)(3)=12$

Hence, option b is correct

Therefore, option b is the required answer.

8 0

3 years ago

Read 2 more answers

The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?

adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)$

$\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}$

$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$