The answer is the letter c
Answer:
A bomb that is dropped from a moving helicopter doesn't fall directly downward rather it follows the parabolic path as it were thrown horizontally from a height with certain initial velocity. Therefore, the bomb should be dropped from farther distance equal to the horizontal range before the helicopter reaches above the target.
You should solve this like you would any algebraic expression. Divide both sides by acceleration (a) and you will isolate the mass (m) to one side. Now divide the force (f) by acceleration (a).
F/a=m
Answer:
Explanation:
Given
ambient Pressure =98.10 kPa
(a)gauge pressure 152 kPa
we know
Absolute pressure=gauge pressure+Vacuum Pressure
=152+98.10=250.1 kPa or 36.27 psi
(b)=67.5 Torr or 8.99 kpa
as 1 Torr is 0.133 kPa
=8.99+98.10=107.09 kPa or 15.53 psi
(c)=0.1 bar or 10 kPa
Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi
as 1 kPa is equal to 0.145 psi
(d)=0.84 atm or 85.113 kPa
as 1 atm is equal to 101.325 kPa
=98.10-85.11=12.99 kPa or 1.88 psi
If a simple machine reduces the strength of a force, "<span>the distance over which the force is applied" must be increased in order to keep the work constant.
In short, Your Answer would be Option A
Hope this helps!</span>