How is a protein structured from an amino acid "string"?

A sprinf has a potential energy of 84.08 J and a constant of 342.25 N/m. How far it been stretched? Use potential energy elastic

valina [46]

The spring has been stretched 0.701 m

Explanation:

The elastic potential energy of a spring is the potential energy stored in the spring due to its compression/stretching. It is calculated as

$E=\frac{1}{2}kx^2$

where

k is the spring constant

x is the elongation of the spring with respect to its equilibrium position

For the spring in this problem, we have:

E = 84.08 J (potential energy)

k = 342.25 N/m (spring constant)

Therefore, its elongation is:

$x=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(84.08)}{342.25}}=0.701 m$

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

8 0

3 years ago

Find the speed of a wave (in meters/second) whose wavelength is 4 meters and

Gemiola [76]

Wave speed = (wavelength) x (frequency)

Wave speed = (4 m) x (3.5 /s)

<em>Wave speed = 14.0 m/s</em>

8 0

3 years ago

As in Problem A above, a block of mass M starts from rest and is pushed up a frictionless ramp inclined at an angle θ above the

Tasya [4]

Answer:

A(i)

The solution to this question is shown on the second uploaded image

A(ii)

The final speed is $v = \sqrt{2L (\frac{F}{M} - gsin\theta )}$

B

The block speed after a distance L is $v= \sqrt{2L (\frac{F}{M} -gsin \theta )}$

Explanation:

From the question

The net force i the x-direction is mathematically represented as

$F_{net} = Ma$

From the the diagram in the second uploaded image we see that

$F_{net} = F - Mgsin \theta$

Therefore

$F- Mgsin\theta = Ma$

Making a the subject

$a = \frac{F}{M} - gsin\theta$

Applying the law of motion

$v^2 =u^2 + 2as$

where u = 0 m/s and s =L

$v^2 = 0 + 2(\frac{F}{M} - gsin \theta )L$

=> $v = \sqrt{2L (\frac{F}{M} - gsin\theta )}$

According to Energy conservation law and work theorem

Workdone by F + Workdone by gravity = change in kinetic energy

Mathematically this is given as

$F * L - (mgsin \theta)L = \frac{1}{2} M (v^2-u^2)$

Since u = 0 m/s

$L (\frac{F}{M} - gsin \theta ) = \frac{1}{2} v^2$

$v= \sqrt{2L (\frac{F}{M} -gsin \theta )}$

5 0

3 years ago

an airplane is moving at a speed of 75 m/s. as it. lands on a. runwsys. if. the runway is. 500m long, what is the acceleration o

bezimeni [28]

Answer: 0.075

explanation:

you can use one of the equations of motion.

2as =v^2 - u^2

we shall make acceleration the subject as that's what we need to find out

a = (v^2 - u^2) / (2 × s)

now substitute the given values:

final speed would be zero as the airplane stops.

a = (75 - 0) / ( 2 × 500)

a = 75 ÷ 1000

a = 0.075 meters per second squared.

4 0

3 years ago

An inventor claims to have invented a heat engine that receives 750kJ of heat from a source at 400K and produces 250kJ of net wo

IRISSAK [1]

Answer:

the claim is not valid or reasonable.

Explanation:

In order to test the claim we will find the maximum and actual efficiencies. maximum efficiency of a heat engine can be found as:

η(max) = 1 - T₁/T₂

where,

η(max) = maximum efficiency = ?

T₁ = Sink Temperature = 300 K

T₂ = Source Temperature = 400 K

Therefore,

η(max) = 1 - 300 K/400 K

η(max) = 0.25 = 25%

Now, we calculate the actual frequency of the engine:

η = W/Q

where,

W = Net Work = 250 KJ

Q = Heat Received = 750 KJ

Therefore,

η = 250 KJ/750 KJ

η = 0.333 = 33.3 %

η > η(max)

The actual efficiency of a heat engine can never be greater than its Carnot efficiency or the maximum efficiency.

<u>Therefore, the claim is not valid or reasonable.</u>

3 0

3 years ago