This is
{HH, TT, TH, HT} where H = head and T = tail
Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Answer:
I believe is A.
Step-by-step explanation:
you will have x^2 (which is the big square) + 1x (which is the lower line) + 3x (which are the 3 line verticals) + 3 (which are the 3 squares)
Answer:
58 students were in each bus
Step-by-step explanation:
First, you'd have to subtract 29 from 551. This gives you 522. Then, you'd simply have to divide 522 by 9. 5 cannot go into 9 so we drag down the 2, 9 can go into 52 5 times. Then, you'll be left with 7, so you bring down the last digit, 2. 9 goes into 72 exactly 8 times.
Answer:
25.6 units
Step-by-step explanation:
From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).
First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:
where
are the coordinates of the first point
are the coordinates of the second point
- For AB:
- For BC:
- For AC:
Next, now that we have our lengths, we can add them to find the perimeter of our triangle:
We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.