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2 years ago

Give a geometric interpretation of the triangle inequality

1 answer:

6 0

The sides must be long enough to make a triangle. (If the sides are not long enough, they won't meet, so cannot form a triangle.)

_____

If your version of the triangle inequality includes the "or equal to" case, then the segments must be long enough to meet, even though the result may look like a line segment.

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What is the sum of the of the infinite geometric series 0.7+0.07+0.007+...?

andrew11 [14]

Answer:

Step-by-step explanation:

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2 years ago

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Len [333]

Answer:

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Step-by-step explanation:

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2 years ago

If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.

Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

$x=\dfrac{k}{y}$ , k is constant of proportionality

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

$y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6$

So, the value of y is 6 when x is 5.

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2 years ago

A smaller triangle is cut out of a larger triangle. The larger triangle is a right triangle with side lengths of 5 millimeters a

iren [92.7K]

Answer:

Sorry if this is late, but it's 24mm2

Step-by-step explanation:

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2 years ago

Read 2 more answers

Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

4 0

3 years ago