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Vedmedyk [2.9K]
3 years ago
6

What is X if

Mathematics
1 answer:
umka2103 [35]3 years ago
7 0

Answer:

X = \begin{bmatrix} - 4 & 1 \\ - 2 & - 7\end{bmatrix}

Step-by-step explanation:

\begin{bmatrix} - 1 & - 2\\ 4 & 8\end{bmatrix} +X = \begin{bmatrix} - 5 & - 1\\ 2 & 1\end{bmatrix}

X = \begin{bmatrix} - 5 & - 1\\ 2 & 1\end{bmatrix}-\begin{bmatrix} - 1 & - 2\\ 4 & 8\end{bmatrix}

X = \begin{bmatrix} - 5-(-1) & - 1-(-2)\\ 2-4 & 1-8\end{bmatrix}

X = \begin{bmatrix} - 5+1 & - 1+2\\ 2-4 & 1-8\end{bmatrix}

X = \begin{bmatrix} - 4 & 1 \\ - 2 & - 7\end{bmatrix}

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6 0
3 years ago
Help! Please! Geometry!!
DiKsa [7]

9.

By the Segment Addition Postulate, SAP, we have

XY + YZ = XZ

so

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10.

M is the midpoint of XZ=5 cm so

XM = 5 cm / 2 =  2.5 cm

11.

XY + YM = XM

YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm

12.

The midpoint is just the average of the coordinate A(-3,2), B(5,-4)

M = (A+B)/2 = \left( \dfrac{-3 + 5}{2}, \dfrac{2 + -4}{2} \right)

Answer: M is (1,-1)

You'll have to plot it yourself.

13.

For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.

AB^2 =(5 - -3)^2 + (-4 - 2)^2 = 8^2 + 6^2 = 100

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M is the midpoint of AB so

Answer: AM=MB=5

14.

B is the midpoint of AC.   We have A(-3,2), B(5,-4)

B = (A+C)/2

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5 0
3 years ago
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