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suter [353]
3 years ago
10

Ms. Bridges asked her class to evaluate the expression she wrote on her whiteboard.

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

41

Step-by-step explanation:

PEMDAS parentheses equation multiplication division adding subtraction

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for a coloring activity, Mr. Smith needs 15 boxes of crayons for 25 students. how many boxes does Mrs. Jones need for 30 student
sergejj [24]
18 boxes of crayons for 30 students
8 0
3 years ago
A company has recently been hiring new employees. Today the company has 29% more employees than it did a year ago. If there are
mezya [45]

Answer:

27477

Step-by-step explanation:

Subtract 38700 from 29% = 27477.

5 0
2 years ago
An elevator on the 10th floor goes down 9 floors. Then it goes up 19 floors, down 3, and finally down 12. What floor does it end
Ksivusya [100]
It lands on floor 5.
10-9+19-3-12
1+19-3-12
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17-12
5
4 0
3 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
Pictures of the problem is attached! :)
hjlf

Answer:

Step-by-step explanation:

16 x 28% = 4.48

16 x 72% = 11.52

16 x 172% = 27.52

16 x 128% = 20.48

---------------------------------------------------------------

I dont know for the second one, sorry-

8 0
3 years ago
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