You need to solve this "system of linear equations." In other words, find a point (x,y) that satisfies both 4x-3y=17 and 2x-5y=-11.
Try solution by elimination. Multiply the 2nd equation by -2 to obtain -4x+5y=22. Add this result to the 1st equation. I'd suggest you write this out to see what is happening.
4x-3y=17
-4x+10y=22
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7y=39. Solving for y, we get y=39/7 (a rather awkward fraction).
Now find x. To do this, substitute 39/7 for y in either of the given equations. Solve the resulting equation for x.
Write your solution in the form (x, y): ( ? , 39/7).
Answer:
141.4 sq cm
Step-by-step explanation:
to find the area of the outer circle with a smaller circle inscribed within, you find the area of each and subtract the smaller area from the larger
the radius of the smaller circle is 2
we have to find the radius of the larger circle so we use what we know about its circumference:
C = 2πr
43.96 = 2πr
21.98 = πr
21.98 / π = r
r ≈ 7 cm
now use r = 7 to find area of larger circle:
A = πr²
A = π49
Area of smaller circle: 4π
Area of larger circle without including inner section is 49π - 4π = 45π
45π ≈ 141.4 sq cm
Answer:
24
Step-by-step explanation:
3d
= 3 × 8
= 24
Hope it helps you:)
If (x+4)(x+9) then either x+4 = 0 or x+9 = 0
This is by the zero product property
