Option A
The restaurant Manager can afford at most 10 employees for the day
<em><u>Solution:</u></em>
Given that restaurant manager can spend at most $600 a day for operating costs and payroll
It costs $100 each day to operate the bank and $50 dollars a day for each employee
The given inequality is:
Where , "x" is the number of employees per day
Let us solve the inequality for "x"
Add -100 on both sides of inequality
Divide by 50 on both sides of inequality
Hence the restaurant Manager can afford at most 10 employees for the day
Thus option A is correct
Hello!
The answer is 20/60 simplest form is 1/3
To get 20/60 you must multiply the Numerator by Numerator (4*5) and Denominator by Denominator (5*12). Your answer will be 20/60.
To get 1/3 you must simplify a number that can go into 20 and 60 (which is 10). Divide 20/10 and 60/10 and get 2/6. Simplify 2/6 by 2 and get 1/3.
Answer:
Step-by-step explanation:
n/4 = 16
n = 16 × 4
n = 64
hope this helps
plz mark it as brainliest
He lost 8, so he is at -8, he then gains 15 so add 15 to -8"-8 + 15 = 7
He gains 7 so now add 7 to the total: 7+ 7 = 14
He then loses 4, so now subtract 4 from the total: 14 - 4 = 10
Answer: He gained 10 yards.
ab + ac + ad is the same as a(b + c + d) according to the distributive property
