Answer:
The system has no solution
Step-by-step explanation:
we have

Isolate the variable y

Divide by 2 both sides
---> equation A
---> equation B
Compare the equations
Equation A and equation B have the same slope and different y-intercept
Remember that
If two lines have the same slope, then the lines are parallel
The solution of the system is the intersection point both graphs
In this problem, the lines don't intersect, therefore, the system has no solution
using a graphing tool
The graph in the attached figure
I’m pretty sure it’s 6 bc to calculate the volume it’s pie•radius^2
Answer:
There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
is the Euler number
is the mean in the given time interval.
The problem states that:
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.
To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.
There are 5 weekdays, with a mean of 0.1 calls per day.
The weekend is 2 days long, with a mean of 0.2 calls per day.
So:

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?
This is
. So:


There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
Answer:
12.252, 12.26, 12.387, 12.4
Step-by-step explanation:
These are the only numbers in a series that are always increasing.
The first series (0.13, 0.31, 0.04, 0.5) and fourth series (6.009, 6.015, 6.241, 6.2) all have an area where they decrease (0.04 and 6.2 respectively).
The second series of numbers is in decreasing order, rather than increasing order. This can not be the answer.
Answer:
r⁶
Step-by-step explanation:
Cancel the common factors or r⁹ and r³