Question

While playing pool, you try to shoot the eight ball into the corner pocket.

Answer 1

Answer:

Step-by-step explanation:

to go from (4, 3/4 ) to (6, 0) you need

a line with slope m= (y2-y1)/(x2-x1) = $\frac{3}{4}$ -0 / 4-6 = $\frac{3}{4} /\frac{-2}{1} =\frac{3}{4} *\frac{-1}{2} =\frac{-3}{8}$

use the quation of a line point-slope

(y-y1)=m(x-x1)

substitute m= -3/8 and (x1,y1) with (6,0)

$y=\frac{-3}{8} (x-6)$

Now does point (10,4) where is the aim is verified by this equation?

substitute x=10, y=4 in the equation to check

4= -3(10-6)/8

4= -3*4/8

4=-3/2 this is never true so you do NOT make the shot