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3 years ago

Two spinners are shown. Look at the spinners as you respond to the statements below.

Mathematics

2 answers:

spayn [35]3 years ago

7 0

Answer:
A. false
B. true
C. true
D. false
step-by-step:
A: probability of spinning a 4 on spinner A is 1/4 and probability of spinning a 4 on spinner B is 1/3.
B: there are 2 fours out of 6 possible options so that makes it 2/6, simplify that, it becomes 1/3.
C: 2 and 4 are even numbers so that makes 2/4 possible on spinner A. simplify 2/4 and that becomes 1/2.
D. spinning a 3 on spinner A would make it 1/4 (already simplified). spinning a 3 on spinner B would make it 1/6 (already simplified) therefore spinner A is greater.

8090 [49]3 years ago

3 0

A: false
b: true
c: true
d: false

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Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Use the equation 0 = ?16t2 + 38

mario62 [17]

Answer:

t = 2.5 s

Step-by-step explanation:

Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Its equation is :

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The above equation is a quadratic equation. The general equation is :

$ax^2+bx+c=0$

Here, a = 16, b = 38.8 and c = 3

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$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\\\\t=\dfrac{-38.8\pm \sqrt{(38.8)^2-4\times (-16)\times 3} }{2\times (-16)}\\\\t=\dfrac{-38.8+\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}, \dfrac{-38.8-\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}\\\\t=-0.075\ s,2.5\ s$

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3 years ago

y varies inversely with x. If x is 2.3 when y is 5.1, what is k, the constant of inverse variation? Round your answer to the nea

snow_tiger [21]

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
x=2.3\\
y=5.1
\end{cases}\implies 5.1=\cfrac{k}{2.3}\implies (5.1)(2.3)=k$

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4 years ago

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