Using the hypergeometric distribution, it is found that there is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
For this problem, the parameters are given as follows:
N =A + B = 54, k = 4, n = 4.
The probability of getting exactly two winning numbers with one ticket is P(X = 2), hence:


There is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
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83 and 89 are prime numbers between 80 and 90.
Answer:
HELP ME PLS :
Logan earned $8 for each dog he walked last summer. This summer, he raised his fee to $9 per dog. Express the change in Logan’s fees as a percent. Round to the nearest tenth of a percent.
Step-by-step explanation:
Answer:
7x
Step-by-step explanation:
(5.2 + 6.8)x - (25 ÷ 5)x
12x-(25divied by 5)x
12x-5x
7x
$550/people = price per person
550/25= $22 per person
550/50= $11 per person
550/55= $10 per person