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3 years ago

Why do atoms form ionic and covalent bonds?

Chemistry

2 answers:

slava [35]3 years ago

8 0

To get full valence shells and to become stable

tresset_1 [31]3 years ago

7 0

Explanation: an ionic bond, is when a atom basically gives a electron to another, forms when one atom becomes stable by losing its outer electrons and the other atoms become stable by gaining the electrons covalent bonds form when sharing atoms results in the highest stability possible

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Vinvika [58]

find the answer in the attached image. please mark as brainliest if it is helpful.

7 0

3 years ago

What is a mixture called when it has its different components mixed evenly within the substance? Heterogeneous mixture Homogeneo

larisa86 [58]

It would be considered a Homogeneous Mixture. A mixture with two or more components mixed evenly is a Homogeneous mixture.

3 0

4 years ago

Read 2 more answers

PLS HELP ASAP i really need an answer a correct one

nata0808 [166]

Answer: 67.23 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles of methane}=\frac{48g}{16g/mol}=3moles$

1 mole of methane occupies = 22.4 L

Thus 3 moles of methane occupy = $\frac{22.4}{1}\times 3=67.23L$

Thus volume of 48 grams of methane gas is 67.23 L

6 0

3 years ago

. Which type of rock would be affected the most by the water cycle?

likoan [24]

Answer:

maybe talc because it is the softest type of rock

Explanation:

5 0

3 years ago

The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.

atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

$rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t}$ (2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

$[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt}$ (3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):

$[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M$

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!

3 0

4 years ago