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attashe74 [19]
3 years ago
12

PLS HELP ASAP i really need an answer a correct one

Chemistry
1 answer:
nata0808 [166]3 years ago
6 0

Answer: 67.23 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles of methane}=\frac{48g}{16g/mol}=3moles

1 mole of methane occupies = 22.4 L

Thus 3 moles of methane occupy = \frac{22.4}{1}\times 3=67.23L

Thus volume of 48 grams of methane gas is 67.23 L

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