Question

PLS HELP ASAP i really need an answer a correct one

Answer 1

Answer: 67.23 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles of methane}=\frac{48g}{16g/mol}=3moles$

1 mole of methane occupies = 22.4 L

Thus 3 moles of methane occupy = $\frac{22.4}{1}\times 3=67.23L$

Thus volume of 48 grams of methane gas is 67.23 L