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zepelin [54]
3 years ago
5

Which statement is true of an alpha particle?

Physics
2 answers:
NeX [460]3 years ago
8 0

Answer:

Atoms are made up of various parts; the nucleus contains minute particles ... neutrons, and the atom's outer shell contains other particles called electrons. ... Physical Forms of Radiation; Radioactive Decay; Nuclear Fission; Ionizing Radiation ... of high-energy waves that can travel great distances at the speed of light and ...

Explanation:

DochEvi [55]3 years ago
3 0

Answer: C

Explanation:

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Two blocks are placed at the ends of a horizontal massless board, as in the drawing. The board is kept from rotating and rests o
Andrew [12]

Answer:

The magnitude of the angular acceleration ∝ = \frac{rxF}{2.8[tex]r^{2}}[/tex]

Explanation:

The angular acceleration ∝ is equal to the torque (radius multiplied by force) divided by the mass times the square of the radius. The magnitude of angular acceleration ∝ will have the equation above but we have to replace the mass in the equation by 2.8kg as stated.

7 0
3 years ago
How can the IMA of a first- class lever be increased?
Dimas [21]
IMA = Ideal Mechanical Advantage

First class lever = > F1 * x2 = F2 * x1

Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2

=> F1/F2 = x1 /x2

IMA = F1/F2 = x1/x2

Now you can see the effects of changing F1, F2, x1 and x2.

If you decrease the lengt X1 between the applied effort (F1) and the pivot,  IMA decreases.

If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.

If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.

If you decrease the applied effort (F1) and decrease the distance between it and the pivot  (X1) IMA will decrease.

Answer: Increase the length between the applied effort and the pivot.
4 0
4 years ago
Read 2 more answers
Use the dropdown menus to complete the paragraph about how the troposphere is heated.
Korvikt [17]

Answer:

Radiation

Conduction

Convection

Current

Explanation:Trust me just took the test also can i get brainliest please

4 0
4 years ago
Read 2 more answers
The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center. If
zvonat [6]

Answer:

The distance between their eye and the ceiling is 33.06 m.

Explanation:

Given that,

The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm

Diameter of the eye of pupil, d = 5.1 mm

Wavelength, \lambda=550\ nm

We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :

L=\dfrac{Dd}{1.22\lambda}\\\\L=\dfrac{4.35\times 10^{-3}\times 5.1\times 10^{-3}}{1.22\times 550\times 10^{-9}}\\\\L=33.06\ m

So, the distance between their eye and the ceiling is 33.06 m.

3 0
3 years ago
PE:
ella [17]

Answer:

The answers are:

T, T, F, F, T, T, F, F, T, T, F

Good luck!

7 0
3 years ago
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