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3 years ago

if a bird at a constant speed going north and then turns west keeping the same speed does the momentum change

Physics

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

yes

Explanation:

momentum depends on velocity so when velocity changes (which is when speed or direction changes) momentum changes

for example angular momentum is the momentum due to rotational motion which includes changes in direction

weqwewe [10]3 years ago

3 0

The momentum does not change because he is going the same speed just a different way.

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A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta

My name is Ann [436]

Answer:

a). $K=528.92 \frac{N}{m}$

b). $m=4.84kg$

Explanation:

a).

The work of the spring is find by the formula:

$w_s =\frac{1}{2}*k*x^2$

So knowing the work can find the constant K'

$3.2J =\frac{1}{2}*k*(0.11m)^2$

Solve for K'

$K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}$

$K=528.92 \frac{N}{m}$

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

$F=m*a$

$m=\frac{F}{a}=\frac{K*x}{a}$

$m=\frac{528.9*0.11m}{12m/s^2}$

$m=4.84kg$

8 0

2 years ago

HELP!!

tresset_1 [31]

Answer:

So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3

3 0

2 years ago

How many discovered planets are there

Allisa [31]

We have discovered 786 planets. Most of which were only recently discovered.

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3 years ago

A space probe is fired as a projectile from the Earth's surface with an initial speed of 2.05 104 m/s. What will its speed be wh

Elanso [62]

Answer:

The value is $v = 2.3359 *10^{4} \ m/s$

Explanation:

From the question we are told that

The initial speed is $u = 2.05 *10^{4} \ m/s$

Generally the total energy possessed by the space probe when on earth is mathematically represented as

$T__{E}} = KE__{i}} + KE__{e}}$

Here $KE_i$ is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

$KE_i = \frac{1}{2} * m * u^2$

=> $KE_i = \frac{1}{2} * m * (2.05 *10^{4})^2$

=> $KE_i = 2.101 *10^{8} \ \ m \ \ J$

And $KE_e$ is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

$KE_e = \frac{1}{2} * m * v_e^2$

Here $v_e$ is the escape velocity from earth which has a value $v_e = 11.2 *10^{3} \ m/s$

=> $KE_e = \frac{1}{2} * m * (11.3 *10^{3})^2$

=> $KE_e = 6.272 *10^{7} \ \ m \ \ J$

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

$KE_p = \frac{1}{2} * m * v^2$

Generally from the law energy conservation we have that

$T__{E}} = KE_p$

$2.101 *10^{8} m + 6.272 *10^{7} m = \frac{1}{2} * m * v^2$

=> $5.4564 *10^{8} = v^2$

=> $v = \sqrt{5.4564 *10^{8}}$

=> $v = 2.3359 *10^{4} \ m/s$

4 0

2 years ago

In the presence of a dielectric, the capacitance of a electric field inside the plates now is: a) Less b) More c) Same as the el

Nesterboy [21]

Answer:

Explanation:

As the dielectric is inserted between the plates of a capacitor, the capacitance becomes K times and the electric field between the plates becomes 1 / K times the original value. Where, K be the dielectric constant.

6 0

3 years ago