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3 years ago

if a bird at a constant speed going north and then turns west keeping the same speed does the momentum change

Physics

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

yes

Explanation:

momentum depends on velocity so when velocity changes (which is when speed or direction changes) momentum changes

for example angular momentum is the momentum due to rotational motion which includes changes in direction

weqwewe [10]3 years ago

3 0

The momentum does not change because he is going the same speed just a different way.

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Do the proton and the neutron have exactly the same mass? How do the masses of the proton and the neutron compare to the mass of

True [87]

Answer:

Explanation:

mas of proton = 1.673 x 10^-27 kg

mass of neutron = 1.675 x 10^-27 kg

mass of electron = 9.1 x 10^-31 kg

(a) the mass of proton and the mass of neutron is not exactly same.

(b) mass of proton = 1838.46 x mass of electron

mass of neutron = 1840.65 x mass of electron

(c) As proton and neutrons are more massive than the electrons, so the protons and the neutrons has the greatest contribution of mass of an atom.

(d) The greatest contribution to the chemical properties of an atom is due to the electrons.

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3 years ago

A car is filled up with 20 gallons of gas. The car uses .25 gallons per minute. How much time will the car travel ?

Nitella [24]

20/.25 is 80, so the car will travel 80 minutes.

8 0

3 years ago

What is the distance traveled per unit time called?

Jobisdone [24]

The distance traveled per unit time is called speed.
Hope this helps you!

6 0

3 years ago

The 20-g bullet is travelling at 400 m/s when it becomes embedded in the 2-kg stationary block. The coefficient of kinetic frict

nikklg [1K]

Answer:

The distance the block will slide before it stops is 3.3343 m

Explanation:

Given;

mass of bullet, m₁ = 20-g = 0.02 kg

speed of the bullet, u₁ = 400 m/s

mass of block, m₂ = 2-kg

coefficient of kinetic friction, μk = 0.24

Step 1:

Determine the speed of the bullet-block system:

From the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the speed of the bullet-block system after collision

(0.02 x 400) + (2 x 0) = v (0.02 + 2)

8 = v (2.02)

v = 8/2.02

v = 3.9604 m/s

Step 2:

Determine the time required for the bullet-block system to stop

Apply the principle of conservation momentum of the system

$v(m_1+m_2) -F_kt = v_f(m_1 +m_2)\\\\v(m_1+m_2) -N \mu_kt = v_f(m_1 +m_2)\\\\v(m_1+m_2) -g(m_1 +m_2) \mu_kt = v_f(m_1 +m_2)\\\\3.9604(2.02)-9.8(2.02)0.24t = v_f(2.02)\\\\8 - 4.751t = 2.02v_f\\\\3.9604 - 2.352t = v_f$

when the system stops, vf = 0

3.9604 -2.352t = 0

2.352t = 3.9604

t = 3.9604/2.352

t = 1.684 s

Thus, time required for the system to stop is 1.684 s

Finally, determine the distance the block will slide before it stops

From kinematic, distance is the product of speed and time

$S = \int\limits {v} \, dt \\\\S = \int\limits^t_0 {(3.9604-2.352t)} \, dt\\\\ S = 3.9604t - 1.176t^2$

Now, recall that t = 1.684 s

S = 3.9604(1.684) - 1.176(1.684)²

S = 6.6693 - 3.3350

S = 3.3343 m

Thus, the distance the block will slide before it stops is 3.3343 m

3 0

3 years ago

Read 2 more answers

. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in

kupik [55]

Answer:

Explanation:

The position is $r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}$ .

The velocity is the first time-derivative of r(t).

$v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}$

The acceleration is the first time-derivative of the velocity.

$a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}$

Since a(t) does not have the variable t, it is constant. Hence, at any time,

$a = -16\hat{j}$

Its magnitude is 16 m/s².

4 0

3 years ago